Math Puzzle questions may aid you in your academic career as a teacher, whether in elementary school, secondary school, or upper secondary school. However, it develops a habit of applying your thinking to every challenge you confront in your life.

This practice will help you stand in the front row of the competition era in higher secondary school. Since you are accustomed to using your head, and in every tournament, they test thinking skills rather than just cramming up abilities. Le’s check some of the benefits that math puzzles provide.

Benefits of Math Puzzles

  • One advantage of employing funny math questions and answers in the classroom/curriculum is that they help students improve their reading and problem-solving abilities. 
  • If the math puzzle games get connected to your curriculum, they will work as a practice and help you improve your accuracy.
  • Furthermore, they promote critical thinking abilities and can give motivation by making arithmetic enjoyable.
  • It will sharpen your thinking, allowing you to tackle basic tasks more readily and enhancing brain efficiency.

1. How many times can you remove 10 from 100?

Answer – 1 Time

Explanation – 

If we go through the steps methodically, the answer is simply one. 

If we remove 10 from 100 for the first time, there will be no 100 to subtract from.

As a result, we can only deduct 10 from 100 once.

2. Find the following two numbers in the series: 1, 8, 11, 69, 88, 96, 101, 111, 181,…

Answer – 609, 619

Explanation – The following two numbers in the sequence are 609 and 619. When numerals are turned upside down, they all look the same (known as invertible numbers). Only the numbers 1, 6, 8, 9, and 0 indicate digits that, when inverted, create the same or a different digit (as in the case of 6 and 9).

3. Two fathers and two sons sat down to breakfast eggs. They ate three eggs, one for each of them. It is up to you to figure out how.

Answer & Explanation – 

One of the ‘fathers’ is a grandfather as well. As a result, the other parent is both a son and a grandfather to his grandson. In other words, the single father is a son as well as a parent.

4. In a certain country, 1/2 of 5 equals 3. What is the value of 1/3 of 10 if the same percentage holds?

Answer – 4

Explanation – 

Let 1/3(10) = x 

=> 3x = 10

Given that 1/2(5)=3

 Therefore, 5/2x = 10 

=> x = 10/3 = 4.

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5. Kapoor ate half a parantha on Monday. On Tuesday, he ate half of what was left, and so on. He stuck to this routine for a week. How much parantha would he have consumed over the week?

Answer – 99.22%

Explanation – 

On Monday, Kapoor ate half a parantha. He would have eaten half of the remaining parantha, or 1/4 of the original parantha, on Tuesday. 

Similarly, on Wednesday, he would have eaten 1/8 of the original parantha, and so on for the next seven days.

The total number of paranthas Kapoor consumed over the week is 

= 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128

 = 127/128 = 99.22 percent of the initial parantha.

6. What is the lowest number that has a leftover of 30 when divided by 35, the remainder 40 when split by 45, and 50 when divided by 55?

Answer – 3460

Explanation – 

The simplest method is to take the Least Common Multiple of 35, 45, and 55 and deduct 5 from it. 

3465 is the LCM of, 35,45, and 55. 

As a result, the needed number is 3460.

7. If 18 monkeys can eat 18 bananas in 18 hours, then in how many hours 79 Monkeys can eat 79 bananas?

Answer – 18 hrs

Explanation – 

According to the findings, 18 monkeys can consume 18 bananas in 18 hours.

=> 1 Monkey can consume 1 banana in 18 hours

=> 79 Monkeys can consume 79 bananas in 18 hours

8. There are eight balls that are exactly the same. One of the balls is overweight. There are just two weighing opportunities in the weighing machine. How can I locate the overweight ball?

Answer & Explanation – 

  • First, weigh three balls against three balls. 
  • If the ball contains one of these six balls, then take the three weighing over balls and weigh the ball 1 against 1. 
  • If the balls are not equal and one of them weighs more, it is the overweight ball; 
  • otherwise, the one not weighed is the ball. 
  • If the 3 against 3 balls were equal, then weigh the two balls to find the overweight ball.

9. If

    2 + 3 = 10

    6 + 3 = 54

    8 + 3 = 88

    Then

    9 + 7 = ?

Answer – 144

Explanation – 

In the given math riddle, the logic is

2 + 3 = 10 => (2 + 3) * 2 = 10

6 + 3 = 54 => (6 + 3) * 6 = 54

8 + 3 = 88 =>  (8 + 3) * 8 = 88

Similarly,

9 + 7  => (9 + 7) * 9 = 16 x 9 = 144.

10. Jim, Jeanne, Louis, and Anne are planning to cross the bridge at night. They just have a single torch light with them. The bridge can only be crossed by 2 people at the same time. To cross the bridge, they’ll need to use a torch. They all walk at various speeds. Jim needs one minute, Jeanne requires two minutes, Louis requires five minutes, and Anne requires ten minutes. A couple must stroll together at a slower person’s pace. How are these folks able to cross the bridge in 17 minutes?

Answer – 17 Minutes

Explanation – 

  • It takes Jim and Jeanne 2 minutes to walk across the bridge.
  • Jim returns 1 minute later with the torchlight.
  • Then Louis and Anne stroll for 10 minutes across the bridge.
  • Jeanne returns with the torchlight after 2 minutes.
  • Finally, Jim and Jeanne stroll for 2 minutes across the bridge.
  • 2 + 1 + 10 + 2 + 2 = 17 minutes total

11. A gathering of 15 people includes two sisters. How many different ways can the group be organized in a circle so that there is only one person between the two sisters?

Answer – 2 * 13! ways

Explanation – 

13 persons may be positioned in 12! different ways around a circle. 

The two sisters may be placed in precisely 13 different ways. 

The sisters can be placed in 2! different ways. 

As a result, the total number of possibilities is 12! * 2 * 13 = 2 * 13!

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Hey ! This is Prince. I am an active, spontaneous, results-oriented freelance writer. Thank you for reading my blog up to the end.

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